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two-sum.jsbinary-search.py
✓ ACCEPTED
function twoSum(nums, target) {
  const seen = new Map();
  for (let i = 0; i < nums.length; i++) {
    const need = target - nums[i];
    if (seen.has(need))
      return [seen.get(need), i];
    seen.set(nums[i], i);
  }
}

// ✓ 12/12 tests · O(n) time · O(n) space
JavaScriptLn 8, Col 1UTF-8

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Two Sum solved

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JSJavaScriptTSTypeScriptPYPythonJAJavaCCCPC++CSC#GOGoPHPHPRSRustKTKotlinSWSwiftJSJavaScriptTSTypeScriptPYPythonJAJavaCCCPC++CSC#GOGoPHPHPRSRustKTKotlinSWSwift

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solution.py
def maxProfit(prices):
    min_price = float("inf")
    max_profit = 0
    for price in prices:
        min_price = min(min_price, price)
        max_profit = max(max_profit, price - min_price)
    return max_profit

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Two SumToday
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Merge K ListsDay 14

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Why is my solution O(n²)?
Your nested loop checks every pair. Use a hash map to look up complements in O(1) — bringing it to O(n). 🎯
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My DFS keeps timing out on large graphs
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